99 Bottles of Beer
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"99 Bottles of Beer" to popularna piosenka angielska, zazwyczaj śpiewana w czasie długich podróży w celu "zabicia czasu".
- 99 bottles of beer on the wall, 99 bottles of beer. Take one down and pass it around - 98 bottles of beer on the wall.
- 98 bottles of beer on the wall, 98 bottles of beer. Take one down and pass it around - 97 bottles of beer on the wall.
- ...
- 2 bottles of beer on the wall, 2 bottles of beer. Take one down and pass it around - 1 bottle of beer on the wall.
- 1 bottle of beer on the wall, 1 bottle of beer. Take it down and pass it around - no more bottles of beer on the wall.
Każda linijka, z wyjątkiem być może ostatnich, różni się tylko liczbą butelek piwa.
Generacja tego wierszyka jest jednym ze standardowych zadań, na których demonstruje się składnię języków programowania.
[edytuj] ABAP
data counter type i value 99.
do 99 times.
write:
/(2) counter, 'bottles of beer on the wall',
/(2) counter, 'bottles of beer!',
/ 'Take one down, pass it around.'.
subtract 1 from counter.
if counter ge 1.
write: /(2) counter, 'bottles of beer on the wall!'.
else.
write / 'No more bottles of beer on the wall!'.
endif.
skip 2.
enddo.
[edytuj] Ada
program należy zapisać jako "program.adb"
with ada.text_io,ada.integer_text_io; use ada.text_io,ada.integer_text_io; procedure program is k:integer:=99; begin while k/=1 loop put(k); put(" bottles of beer on the wall, "); new_line; put(k); put(" bottles of beer. Take one down, pass it around - "); k:=k-1; if k=1 then put(integer'image(k)&" bottle of beer on the wall!"); new_line; put_line("1 bottle of beer on the wall, 1 bottle of beer."); put_line("Take it down, pass it around. No more bottles of beer on the wall!"); else put(integer'image(k)&" bottles of beer on the wall!"); new_line; end if; end loop; end program;
[edytuj] Asembler (nasm)
section .text global _start print: mov ebx, 01h mov eax, 04h int 80h ret IntToStr: add ebx, 1 mov ecx, 10 cmp eax, 10 jb a2 jmp a1 a2: mov byte [integer], 0 a1: xor edx, edx div ecx or dl, 30h mov [ebx], dl dec ebx test eax, eax jnz a1 ret _start: mov ecx, [var] main: mov [var], ecx mov eax, ecx mov ebx, integer call IntToStr mov edx, integerl mov ecx, integer call print mov edx, str1l mov ecx, str1 call print mov edx, integerl mov ecx, integer call print mov edx, str2l mov ecx, str2 call print mov eax, [var] dec eax mov ebx, integer call IntToStr mov edx, integerl mov ecx, integer call print mov edx, str3l mov ecx, str3 call print mov ecx, [var] dec ecx test ecx, ecx jnz main mov edx, str4l mov ecx, str4 call print mov eax, 01h mov ebx, 00h int 80h section .data str1 db ' bottles of beer on the wall, ' str1l equ $-str1 str2 db ' bottles of beer.', 0ah, 'Take one down and pass it around, ' str2l equ $-str2 str3 db ' bottles of beer on the wall.', 0ah, 0ah str3l equ $-str3 str4 db 'No more bottles of beer on the wall, no more bottles of beer.', 0ah, 'Go to the store and buy some more, 99 bottles of beer on the wall.',0ah str4l equ $-str4 integer times 2 db 0 integerl equ $-integer var dd 63h
[edytuj] AutoIt
$a = ' bottle' $b = ' of beer' $c = ' on the wall' $d = '. Take one down and pass it around - ' $e = 'no more' For $n = 99 To 1 Step -1 $text = $n & $a & 's' & $b & $c & ', ' & $n & $a & 's' & $b & $d & $n - 1 & $a & 's' & $b & $c & '.' Select Case $n=2 $text = $n & $a & 's' & $b & $c & ', ' & $n & $a & 's' & $b & $d & $n - 1 & $a & $b & $c & '.' Case $n=1 $text = $n & $a & $b & $c & ', ' & $n & $a & $b & $d & $e & $a & 's' & $b & $c & '.' EndSelect MsgBox(0, '99 bottles of beer', $text) Next
[edytuj] awk
echo 99 | awk '{
b="bottle";
e="of beer";
w="on the wall";
t="Take one down, pass it around.";
for (i=$1; i>0; i--) {
if (i>1) {s="s"} else {s=""};
print i, b s, e, w ".";
print i, b s, e "!";
print t;
if (i!=2) {s="s"} else {s=""};
if (i==1) {n="No more"} else {n=i-1};
print n, b s, e, w "!\n"
}
}'
[edytuj] bash
#!/bin/bash b=bottle e=of\ beer w=on\ the\ wall t="Take one down, pass it around." for i in `seq 1 99 | tac`; do # because `seq 99 1` doesn't seem to be portable. if test $i -gt 1; then s=s; else unset s; fi echo "$i $b$s $e $w." echo "$i $b$s $e"'!' echo $t if test $i -ne 2; then s=s; else unset s; fi if test $i -eq 1; then n=No\ more; else n=`expr $i - 1`; fi echo "$n $b$s $e $w"'!' echo done
[edytuj] BASIC
[edytuj] prosty BASIC
10 FOR i% = 99 TO 2 STEP -1 20 PRINT i%; " bottles of beer on the wall" 30 PRINT i%; " bottles of beer!" 40 PRINT "Take one down, pass it around. "; (i% - 1); " bottles of beer on the wall!" 50 NEXT i% 60 PRINT "1 bottle of beer on the wall" 70 PRINT "1 bottle of beer!" 80 PRINT "Take it down, pass it around. No more bottles of beer on the wall!" 90 END
[edytuj] DarkBasic Professional
global t$ as string
for bottles=99 to 1 step -1
t$=isPlural(bottles)
t$=t$+" of beer on the wall"
print t$;", ";t$
print "Take one down and pass it around, ";
if bottles-1>0
print isPlural(bottles-1);
print " of beer on the wall"
else
print "No more bottles of beer on the wall"
endif
sync
next bottles
print "No more bottles of beer on the wall, no more bottles of beer."
print "Go to the store and buy some more, 99 bottles of beer on the wall..."
wait key
end
function isPlural(bottles as integer)
local temp$ as string
temp$=str$(bottles)+" bottle"
if bottles>1
temp$=temp$+"s"
endif
endfunction temp$
[edytuj] Visual Basic .NET
Sub Main() For i As Integer = 99 To 1 Step -1 Console.Write(i.ToString + " bottles of beer on the wall, ") Console.Write(i.ToString + " bottles of beer! ") Console.WriteLine("Take one down, pass it around - " + (i - 1).ToString + " bottles of beer on the wall!") Next Console.Write("1 bottle of beer on the wall, ") Console.Write("1 bottle of beer! ") Console.WriteLine("Take it down, pass it around - no more bottles of beer on the wall!") End Sub
[edytuj] Blitz Basic
For i=99 To 2 Step -1 Print i + " bottles of beer on the wall" Print i + " bottles of beer!" Print "Take one down, pass it around. " + (i - 1) + " bottles of beer on the wall!" Next Print "1 bottle of beer on the wall" Print "1 bottle of beer!" Print "Take it down, pass it around. No more bottles of beer on the wall!"
[edytuj] Batch
Poniższy przykład nie będzie pracować poprawnie na systemie Windows 98 i wcześniejszych wersjach pliku command.com, ponieważ polecenie “set” nie posiada opcji “/a”.
@echo off set now=99 set multi=s :loop echo %now% bottle%multi% of beer on the wall. %now% bottle%multi% of beer! set /a now=now-1 if %now%==0 goto outloop if %now%==1 set multi= echo Take one down, pass it around. %now% bottle%multi% of beer on the wall! goto loop :outloop echo Take it down, pass it around. No more bottles of beer on the wall!
[edytuj] Boo
s="s"
for i in range(99, 1):
if i<99:
s="" if i==1
print "${i} bottle${s} of beer on the wall!"
print "${i} bottle${s} of beer on the wall!"
print "${i} bottle${s} of beer!"
print "Take one down, pass it around."
print "No more bottles of beer on the wall."
[edytuj] C
#include <stdio.h> int main() { int i; for (i=99; i > 1; --i) { printf("%d bottles of beer on the wall,\t%d",i,i); printf(" bottles of beer.\n Take one down, pass it around - "); printf("%d bottles of beer on the wall!\n", i); } printf("1 bottle of beer on the wall,\t"); printf("1 bottle of beer.\n"); printf("Take it down, pass it around. No more bottles of beer on the wall!\n"); return 0; }
[edytuj] C++
#include <iostream> using namespace std; int main() { for(int i = 99; i > 1;) { cout << i << " bottles of beer on the wall\n"; cout << i << " bottles of beer!\n"; cout << "Take one down, pass it around. " << --i; if (i==1) break; cout << " bottles of beer on the wall!\n"; } cout << "1 bottle of beer on the wall\n" << "1 bottle of beer.\n" << "Take it down, pass it around. No more bottles of beer on the wall!" << endl; cin.ignore(); return 0; }
[edytuj] C#
static int Main(string[] args) { for (int i = 99; i > 1; i--) { Console.WriteLine("{0} bottles of beer on the wall, {0} bottles of beer. ", i); Console.WriteLine("Take one down and pass it around - {0} bottles of beer on the wall.", i-1); }; Console.WriteLine("1 bottle of beer on the wall, 1 bottle of beer. "); Console.WriteLine("Take it down and pass it around - no more bottles of beer on the wall. "); Console.ReadKey(); return 0; }
[edytuj] D
import std.stdio; void main() { for (int i = 99; i > 0; ) { writefln(i, " bottles of beer on the wall,"); writefln(i, " bottles of beer!"); writefln("Take one down, pass it around; ", (--i == 0 ? "No more" : i), " bottles of beer on the wall!"); } }
[edytuj] Delphi
program BottlesOfBeer; {$APPTYPE CONSOLE} uses SysUtils; var i : integer; begin for I := 99 downto 2 do begin Writeln(IntToStr(i)+' bottles of beer on the wall, '+ IntToStr(i)+' bottles of beer. Take one down and pass it around - '+ IntToStr((i-1))+' bottles of beer on the wall.'); end; Writeln('1 bottle of beer on the wall, 1 bottle of beer. ' +'Take it down and pass it around - no more bottles of beer on the wall.'); Readln; end.
[edytuj] Fortran
program Beeeer character*16 :: i1string, i2string integer :: i do i=99, 2, -1 write(i1string,*) i write(i2string,*) i-1 print *, trim(adjustl(i1string)), " bottles of beer on the wall, ", & trim(adjustl(i1string)), " bottles of beer. ", & "Take one down and pass it around ", trim(adjustl(i2string)), " bottles of beer on the wall." end do print *, "1 bottle of beer on the wall, 1 bottle of beer.", & "Take it down and pass it around - no more bottles of beer on the wall." end
[edytuj] Haskell
wall n p d = n ++ " bottle" ++ p ++ " of beer on the wall" ++ d beer n p = n ++ " bottle" ++ p ++ " of beer!\n" more = "Take one down, pass it around.\n" _bottles_ (1,s) = (0, s ++ (wall "1" "" ".\n") ++ (beer "1" "" ) ++ more ++ (wall "No more" "s" "!")) _bottles_ (2,s) = _bottles_ (1, s ++ (wall "2" "s" ".\n") ++ (beer "2" "s") ++ more ++ (wall "1" "" "!\n\n")) _bottles_ (n,s) = _bottles_ (n-1,s ++ (wall (show n) "s" ".\n") ++ (beer (show n) "s") ++ more ++ (wall (show (n-1)) "s" "!\n\n")) bottles n = snd (_bottles_ (n,"")) main = putStr (bottles 99)
[edytuj] HQ9+
9
[edytuj] J
bob =: ": , ' bottles of beer'"_ -. 1&= # 's'"_ bobw=: bob , ' on the wall'"_ beer=: bobw , ', '"_ , bob , '; take one down and pass it around, '"_ , bobw@<:
beer"0 (- i.) 99
[edytuj] Java
public class Beer { public static void main(String[] args) { for(int i = 99; i > 1; i--) { System.out.println(i + " bottles of beer on the wall!"); System.out.println(i + " bottles of beer!"); System.out.println("Take one down, pass it around. "+(i-1)+" bottles of beer on the wall!"); } System.out.println("1 bottle of beer on the wall!"); System.out.println("1 bottle of beer!"); System.out.println("Take it down, pass it around. No more bottles of beer on the wall!"); } }
[edytuj] JavaScript
<script type="text/javascript"> for(i = 99; i > 1; i--) document.write(i + ' bottles of beer on the wall, ' + i +' bottles of beer. Take one down and pass it around - ' + (i-1) + ' bottles of beer on the wall. <br />'); document.write('1 bottle of beer on the wall, 1 bottle of beer. ' +'Take it down and pass it around - no more bottles of beer on the wall.'); </script>
[edytuj] Lisp
[edytuj] Common Lisp
(loop for i from 99 downto 1 do (format t "~&~D bottle~:P of beer on the wall, ~:*~D bottle~:P of beer.~%" i) (format t "Take one down and pass it around, ~[no more~:;~:*~D~] bottle~:P of beer on the wall." (1- i)))
Albo:
(defun bottle-song (&optional (in-stock 99) (stream *standard-output*)) ;; Original idea and primary coding by Geoff Summerhayes ;; <sumrnot@hotmail.com> ;; Formatting idea by Fred Gilham <gilham@snapdragon.csl.sri.com> ;; Actual formatting & minor recoding by Kent M Pitman ;; <pitman@world.std.com> (format stream "-----~2%~ ~{~&~1&~ ~[~^~:;~ ~1:*~@(~ ~R~) bo~ ttle~:P o~ f beer on t~ he wall~01:*~[.~ ~:;,~%~1:*~@(~R~ ~) bottle~:*~P ~ of beer.~%You t~ ake one down, p~ ass it around, ~ ~01%~[*No* more~ ~:;~:01*~@(~R~)~ ~] bottle~:*~P ~ of beer on the ~ wall.~2&-----~%~ ~1%~:*~]~]~}~0%" (loop for bottle from in-stock downto 0 collect bottle)))
[edytuj] Malbolge
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[edytuj] MATLAB
function bottles % BOTTLES Prints the full lyrics of "99 Bottles of Beer". for i = 99:-1:2 fprintf('%d bottles of beer on the wall\n', i) fprintf('%d bottles of beer!\n', i) fprintf('Take one down, pass it around. %d bottles of beer on the wall!\n', (i - 1)) end fprintf('1 bottle of beer on the wall\n') fprintf('1 bottle of beer!\n') fprintf('Take it down, pass it around. No more bottles of beer on the wall!\n')
[edytuj] M4
divert(-1)
define(`_b_', `$1 bottle$2 of beer')
define(`_w_', `on the wall$1')
define(`_t_', `Take one down, pass it around.')
define(`_bottles_',
`ifelse(1, eval($1>0),
`ifelse(1, eval($1>2),
`define(`_s_', `s')define(`_ss_', `s')define(`_n_', eval($1-1))',
1, eval($1>1),
`define(`_s_', `s')define(`_ss_', `')define(`_n_', eval($1-1))',
`define(`_s_', `')define(`_ss_', `s')define(`_n_', `No more')')dnl
_b_($1, _s_)` '_w_(`.')
_b_($1, _s_)!
_t_
_b_(_n_, _ss_)` '_w_(`!')`
'
_bottles_(eval($1-1))')')
divert(0)dnl
_bottles_(99)dnl
[edytuj] Pascal
program bottles; var i : integer; begin for i := 99 downto 2 do begin writeln(i, ' bottles of beer on the wall'); writeln(i, ' bottles of beer!'); writeln('Take one down, pass it around. ', (i - 1), ' bottles of beer on the wall!'); end; writeln('1 bottle of beer on the wall'); writeln('1 bottle of beer!'); writeln('Take it down, pass it around. No more bottles of beer on the wall!'); end.
[edytuj] Perl
$b="of beer"; $w="on the wall"; print "$_ ",b($_)," $b $w\n$_ ",b($_), "$b\ntake one down, pass it around, ",$_-1," ",b($_-1)," $b $w\n\n" foreach (reverse 1..99); sub b { $x="bottle"; $_[0]==1?$x:$x."s"; }
[edytuj] PHP
<?php for ( $i = 99; $i >= 1; $i-- ) { echo $i . ' bottle' . ( ( $i != 1 ) ? 's' : '') . ' of beer on the wall, ' . $i . ' bottle' . ( ( $i != 1 ) ? 's':'') . ' of beer . '; echo 'Take one down and pass it around - ' . ( ( $i - 1 > 0 ? $i - 1 : 'no' ) ) . ' bottle' . ( ( $i - 1 != 1) ? 's' : '' ) . ' of beer on the wall.'; echo "\n"; } ?>
Alternatywnie:
$i = 99; while ($i > 1) { echo $i . ' bottles of beer on the wall, ' . $i . ' bottles of beer. '; echo 'Take one down and pass it around - ' . --$i . ' bottle' . (($i > 1) ? 's' : '') . ' of beer on the wall.'; echo "\n"; // New line } echo '1 bottle of beer on the wall, 1 bottle of beer. Take it down and pass it around - no more bottles of beer on the wall.';
Opcjonalnie:
<?php for ($i = 99 ; $i >= 1 ; $i--) { echo "{$i} bottle".(($i!=1)?'s':'')." of beer on the wall, ". "{$i} bottle".(($i!=1)?'s':'')." of beer. "; echo "Take one down and pass it around - ".(($i>1)?$i-1:'no more'). " bottle".(($i!=2)?'s':'')." of beer on the wall.\n"; } ?>
[edytuj] PL/SQL
SET serveroutput ON DECLARE k NUMBER:=99; BEGIN WHILE k<>1 LOOP DBMS_OUTPUT.put_line(k||' bottles of beer on the wall, '||k); DBMS_OUTPUT.put_line(' bottles of beer. Take one down, pass it around - '); k:=k-1; IF k=1 THEN DBMS_OUTPUT.put_line(k||' bottle of beer on the wall!'); DBMS_OUTPUT.put_line('1 bottle of beer on the wall, 1 bottle of beer.'); DBMS_OUTPUT.put_line('Take it down, pass it around. No more bottles of beer on the wall!'); ELSE DBMS_OUTPUT.put_line(k||' bottles of beer on the wall!'); END IF; END LOOP; END; /
[edytuj] Python
s = '%d bottles of beer on the wall\n%d bottles of beer!\nTake one down pass it around\n%d bottles of beer on the wall!' print '\n'.join((s % (i, i, i-1) for i in xrange(99, 1, -1)))
[edytuj] Ruby
99.times do |x| count = 100-x print "#{count} bottles of beer on the wall\n#{count} bottles of beer!\nTake one down pass it around\n#{count - 1} #{(count - 1) == 1 ? 'bottle' : 'bottles'} of been on the wall!\n" end
[edytuj] sed
echo 99 | sed -nre ':l
s/^0$//
s/^1$/1_w._1_b__t_No more_W!_/
s/^2$/2_W._2_B__t_1_w!_/
s/^([3-9])$/\1_W._\1_B__t_@\1@_W!_/
s/^([1-9])0$/\10_W._\10_B__t_@\1@9_W!_/
s/^([1-9])([1-9])$/\1\2_W._\1\2_B__t_\1@\2@_W!_/
s/@9@/8/;s/@8@/7/;s/@7@/6/;s/@6@/5/;s/@5@/4/;s/@4@/3/;s/@3@/2/;s/@2@/1/;s/@1@/0/
s/0([1-9])/\1/
s/_W(!|.)_/ bottles of beer on the wall\1\n/g
s/_w(!|.)_/ bottle of beer on the wall\1\n/g
s/_B_/ bottles of beer!\n/
s/_b_/ bottle of beer!\n/
s/_t_/Take one down, pass it around.\n/
p
s/\n/@/g
s/^.*@([0-9]*)[^@]*@$/\1/
/^[0-9]+$/tl
'
[edytuj] Tcl: Tool Command Language
set s "%d bottles of beer on the wall\n%d bottles of beer!\nTake one down pass it around\n%d bottles of beer on the wall!\n" for {set i 99} {$i > 0} {incr i -1} { puts [format $s $i $i [expr $i - 1]] }
[edytuj] TeX
[edytuj] prosty TeX
\newcount\n \def\bottles#1{\edef\o{#1}\n=#1 \ifnum\n>0 \advance\n by -1 \ifnum\n>1\def\s{s}\def\ss{s}\def\m{\number\n}\else \ifnum\n>0\def\s{s}\def\ss{}\def\m{\number\n}\else \def\s{}\def\ss{s}\def\m{No more}\fi\fi \noindent\o\ bottle\s\ of beer on the wall.\par \noindent\o\ bottle\s\ of beer!\par \noindent Take one down, pass it around.\par \noindent\m\ bottle\ss\ of beer on the wall!\par \bigskip \bottles{\number\n}\fi } \bottles{99} \bye
[edytuj] LaTeX
\documentclass{article} \usepackage{ifthen} \newcommand{\bottles}[1]{\newcommand{\s}{s} \newcounter{n}\setcounter{n}{#1} \whiledo{\arabic{n}>0}{ \ifthenelse{\arabic{n}=1}{\renewcommand{\s}{}}{\renewcommand{\s}{s}} \noindent\arabic{n} bottle\s\ of beer on the wall.\\* \arabic{n} bottle\s\ of beer!\\* Take one down, pass it around.\\* \addtocounter{n}{-1} \ifthenelse{\arabic{n}=1}{\renewcommand{\s}{}}{\renewcommand{\s}{s}} \ifthenelse{\arabic{n}=0}{No more}{\arabic{n}} bottle\s\ of beer on the wall!\par \bigskip } } \begin{document}\bottles{99}\end{document}
